洛桑江村齐扎拉分别会见美国参议员戴安斯一行
Current License: CC BY-SA 4.0
4 events
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| 12 hours ago | comment | added | SethK | That's just the wrong basis for this question. There are three mass eigenstates of neutrinos, and the heavier two decay via known SM physics to the lightest one. See 10.1103/PhysRevD.25.766 for an early calculation. | |
| 17 hours ago | comment | added | cconsta1 | @Hearth good point! I thought about it, but didn't include it in my answer because neutrino oscillations just change the flavor of the neutrino, but the neutrino number persists. They don't get destroyed as when, say, a neutron decays into a proton (plus an electron and an electron antineutrino), so the neutron number goes from 1 to 0. In neutrino oscillations, you don't get a decay. | |
| 18 hours ago | comment | added | Hearth | One could argue that neutrino oscillation means they wouldn't count here. | |
| yesterday | history | answered | cconsta1 | CC BY-SA 4.0 |